document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1079993>Question 1079993</A>: <I><SPAN STYLE=\"word-break: break-all;\"> \"A 15 kg toboggan is pulled along the snow at a constant speed by a horizontal force of 22 N. \r<BR>\n" );
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document.write( "How much more force is needed to pull the toboggan if two passengers, one with a mass of 40 kg and the other with a mass of 65 kg are riding on it.\"\r<BR>\n" );
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document.write( "This was a two part question. In part one I had to find the coefficient of kinetic friction between the toboggan and the snow. That was straight forward: using the proper formula it came out to a coefficient of 0.15.  Coefficient = Ff/FN = 22N/147N = 0.15 \r<BR>\n" );
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document.write( "On part two do I add only the new masses together then use  Ff = Mg x coefficient kinetic friction? \r<BR>\n" );
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document.write( "If so I'm looking at \r<BR>\n" );
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document.write( "Ff = 105 kg x 9.80 m/s^2 x 0.15 = 154.35 N  or 132.35 N more than the original\r<BR>\n" );
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document.write( "Or is the question asking me to consider the new mass with the old mass? \r<BR>\n" );
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document.write( "Ff = 120 kg x 9.80 m/s^2 x 0.15 = 176.4 N which is 154.4 N more than the original </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #694254 by </B><A HREF=/tutors/aboutme.mpl?userid=ikleyn><B>ikleyn(52878)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ikleyn><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ikleyn><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=694254\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .<BR>\n" );
document.write( "<PRE STYLE=\"white-space: pre-wrap; white-space: -moz-pre-wrap; white-space: -pre-wrap; white-space: -o-pre-wrap; word-wrap: break-word;\">\r\n" );
document.write( "The normal force produced by 15 kg mass is m*g = 15*9.81 = 147.15 N (newtons)\r\n" );
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document.write( "The kinetic friction coef. = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=22%2F147.15 ALIGN=MIDDLE  ALT=\"22%2F147.15\"   DISABLED_style= \"max-width:90%; height:auto;\" > = 0.15.   CORRECT !!\r\n" );
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document.write( "In the next step (in the Part 2) you need to use the mass of 15 kg + 40 kg + 65 kg.\r\n" );
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