document.write( "Question 1080011: You are an engineer for McDonalds and it is your job to develop a new small coffee cup. The average diameter of a car cup holder is between 10.10 cm and 12 cm. A small cup must hold 225 cm^3 of coffee. What is the height of your cup design?\r
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document.write( "πr^2h=225 cm^3\r
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document.write( "h=v/π5.5^2
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document.write( "h=225/π5.5^2
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document.write( "225/95.03 = 2.37 doesn't make sense
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document.write( "I also tried converting the cm^3 first and came up with 6.0822. I thought I had it correct with dividing 95.03nby 6.0822 to end up with 15.64 cm since that would give me a cup that is 6.2 inches tall, but then I realized I did it backwards... PLEASE help!
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Algebra.Com's Answer #694239 by MathLover1(20850) You can put this solution on YOUR website! \r \n" ); document.write( "\n" ); document.write( "average diameter of a car cup holder is between \n" ); document.write( "\n" ); document.write( "so, average \n" ); document.write( "\n" ); document.write( "if given volume must be \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "and\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "so, the \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |