document.write( "Question 401547: Mr. Wilson is 15 years older than Mr. Connors. Five years from now, Mr. Wilson will be 1 1/2 times as old as Mr. Connors will be then. How old is each man now? \n" ); document.write( "
Algebra.Com's Answer #694232 by TheWastedWizard(1)![]() ![]() You can put this solution on YOUR website! Let c be Mr. Connors' age NOW.\r \n" ); document.write( "\n" ); document.write( "In 15 years: \n" ); document.write( "Mr. Wilson will be 20 + c years old \n" ); document.write( "Mr. Connors will be c + 5 years old\r \n" ); document.write( "\n" ); document.write( "Equation: \n" ); document.write( " 20 + c = 1.5 (c + 5) \n" ); document.write( " 20 + c = 1.5c + 7.5 \n" ); document.write( "12.5 + c = 1.5 c \n" ); document.write( " 12.5 = 0.5c \n" ); document.write( "25 years = c\r \n" ); document.write( "\n" ); document.write( "Mr. Connors is 25 years old NOW. \n" ); document.write( "Mr. Wilson is 15 years older than Mr. Connors, so he is 15 + 25 years. \n" ); document.write( "Mr. Wilson is 40 years old NOW. \n" ); document.write( " |