document.write( "Question 1079870: The inner circumference of a circular race truck is 352m.The truck is everywhere 2.5m wide. Calculate the cost of (I) levelling the truck at the rate of 1.80 per m^2. (II) putting up a fence along the fence along the outer circle of 3.25 per m \n" ); document.write( "
Algebra.Com's Answer #694194 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! The inner circumference of a circular race truck is 352m. The truck is everywhere 2.5m wide. Calculate the cost of (I) leveling the truck at the rate of 1.80 per m^2. (II) putting up a fence along the fence along the outer circle of 3.25 per m \n" ); document.write( "--------------- \n" ); document.write( "The inner circumference of a circular race truck is 352m. \n" ); document.write( "Find the radius of the inside. \n" ); document.write( "C = 2pi*r1 = 352 \n" ); document.write( "r1 = 176/pi meters. \n" ); document.write( "--- \n" ); document.write( "The outside radius r2 = 2.5 + 176/pi meters \n" ); document.write( "---- \n" ); document.write( "Calculate the cost of (I) leveling the truck at the rate of 1.80 per m^2. \n" ); document.write( "The area of the track is the area of the outside circle minun the area of the inside circle. \n" ); document.write( "Area = pi*(r2)^2 - pi*(r1)^2 \n" ); document.write( "Cost = 1.8*Area \n" ); document.write( "------------- \n" ); document.write( "(II) putting up a fence along the fence along the outer circle of 3.25 per m \n" ); document.write( "Outside circumference = 2pi*r2 \n" ); document.write( "Cost = 3.25*C \n" ); document.write( " |