document.write( "Question 1079950: What is the perimeter of a rectangular area rug that is 5+x/2 feet long and 2x-1/3 feet wide. Simplify your answer. \n" ); document.write( "
Algebra.Com's Answer #694183 by MathLover1(20849)\"\" \"About 
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\n" ); document.write( "the perimeter of a rectangle is \"P=2L%2B2W\" where \"L\" is the length and \"W\" is the width\r
\n" ); document.write( "\n" ); document.write( "the perimeter of a rectangular area rug that is \"L=%285%2Bx%29%2F2\" feet long and \"W=%282x-1%29%2F3+\"feet wide will be:\r
\n" ); document.write( "\n" ); document.write( "\"P=cross%282%29%285%2Bx%29%2Fcross%282%29%2B2%282x-1%29%2F3\"\r
\n" ); document.write( "\n" ); document.write( "\"P=%285%2Bx%29%2B%284x-2%29%2F3\"\r
\n" ); document.write( "\n" ); document.write( "\"P=%283%285%2Bx%29%2B%284x-2%29%29%2F3\"\r
\n" ); document.write( "\n" ); document.write( "\"P=%2815%2B3x%2B4x-2%29%2F3\"\r
\n" ); document.write( "\n" ); document.write( "\"P=%287x%2B13%29%2F3\"\r
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