document.write( "Question 1079866: How much of an 20% acid solution and how much of a 60% acid solution should bw mixed together to make 100 liters of a 35% acid solution? \n" ); document.write( "
Algebra.Com's Answer #694159 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
How much of an 20% acid solution and how much of a 60% acid solution should be mixed together to make 100 liters of a 35% acid solution?
\n" ); document.write( ":
\n" ); document.write( "let x = amt of 60% solution
\n" ); document.write( "the total result is 100 l, therefore:
\n" ); document.write( "100-x = amt of 20% solution
\n" ); document.write( ":
\n" ); document.write( "decimal equiv of percent
\n" ); document.write( ".60x + .20(100-x) = .35(100)
\n" ); document.write( ".6x + 20 - .2x = 35
\n" ); document.write( ".6x - .2x = 35 - 20
\n" ); document.write( ".4x = 15
\n" ); document.write( "x = 15/.4
\n" ); document.write( "x = 37.5 liters of 60% solution required
\n" ); document.write( "and
\n" ); document.write( "100 - 37.5 = 62.5 liters of 20% solution
\n" ); document.write( ":
\n" ); document.write( ";
\n" ); document.write( "Check out solutions
\n" ); document.write( ".6(37.5) + .2(62.5) = 35
\n" ); document.write( "22.5 + 12.5 = 35 \n" ); document.write( "
\n" );