document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1079787>Question 1079787</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Use a reference rectangle and the rule of fourths to draw an accurate sketch of the following function through at least one full cycle.\r<BR>\n" );
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document.write( "y = –4 cos t\r<BR>\n" );
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document.write( "y = 4 cos t<BR>\n" );
document.write( "please help me i dont know how to solve this to get an accurate sketch of the ff. function </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #694028 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=694028\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Few things to remember about cosine<BR>\n" );
document.write( "Positive in Q1 and Q4.<BR>\n" );
document.write( "At 45 degrees in those quadrants, it is sqrt(2)/2 and in the other two it is - sqrt(2)/2.<BR>\n" );
document.write( "At 30 degrees in Q4 (300 deg from origin), it is 1/2, and again at 60 degrees.  It is -1/2 at 120 and 240 degrees, 180 degrees apart from those two values<BR>\n" );
document.write( "At 60 degrees (330 in Q4) and at 30 degrees in Q1, it is sqrt(3)/2.  At 150 and 210 it is - sqrt (3)/2<BR>\n" );
document.write( "The amplitude is 4, so it is the cosine graph increased by a factor of 4 in the vertical plane.  This is graphed by radians.<BR>\n" );
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document.write( "The - cos t is the one that is -4 at x=0. </SPAN>\n" );
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