document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=13732>Question 13732</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a rectangle is 86cm.  Twice the width exceeds the length by 2cms. Find the dimensions. I used this equation P=2l+2W, but I don't know how to combine the terms </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #6940 by </B><A HREF=/tutors/aboutme.mpl?userid=LilSkittleMd><B>LilSkittleMd(119)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=LilSkittleMd><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=6940\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> P=2L+2W<BR>\n" );
document.write( "The second equation is 2W=L+2 (Twice the width exceeds the length by 2)<BR>\n" );
document.write( "You need to put this equation into a \"L equals\" or \"W equals\" so you can plug it into the P equation. Use an L equation, it is easier to use. Just subtract 2 from both sides.<BR>\n" );
document.write( "2W-2=L<BR>\n" );
document.write( "Now just put everything together<BR>\n" );
document.write( "86=2(2W-2)+2W<BR>\n" );
document.write( "86=4W-4+2W<BR>\n" );
document.write( "86=6W-4<BR>\n" );
document.write( "90=6W<BR>\n" );
document.write( "15=W<BR>\n" );
document.write( "L=2(15)-2<BR>\n" );
document.write( "L=30-2<BR>\n" );
document.write( "L=28<BR>\n" );
document.write( "The width is 15 cm and the length is 28 cm </SPAN>\n" );
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