document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1079705>Question 1079705</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A young man is 3 years older than his brother. Thirty years from now the sum of their ages will be 111. Find the current ages of the brothers.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #693943 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel1380><B>jorel1380(3719)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel1380><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jorel1380><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=693943\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let n and n+3 be the brother and the young man, respectively. Then<BR>\n" );
document.write( "n+n+3+2(30)=111<BR>\n" );
document.write( "2n=48<BR>\n" );
document.write( "n=24<BR>\n" );
document.write( "The brother is 24; the young man is 27. &#9786;&#9786;&#9786;&#9786; </SPAN>\n" );
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