document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1079717>Question 1079717</A>: <I><SPAN STYLE=\"word-break: break-all;\"> please help me solve my word problem {nine books are to be bought by a student. Some cost $6 each and the remainder cost $6.50 each.If the total amount spend was $56, how many of each book are bought?}<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #693937 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=693937\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the $6 books be x and the books at 6.50 y:<BR>\n" );
document.write( "So we have:<BR>\n" );
document.write( "x + y = 9 subtract y from both sides:<BR>\n" );
document.write( "x = 9 - y<BR>\n" );
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document.write( "6x + 6.50y = 56 substitute for x<BR>\n" );
document.write( "6(9 - y) + 6.50y = 56<BR>\n" );
document.write( "54 - 6y + 6.50y = 56<BR>\n" );
document.write( "0.50y = 2<BR>\n" );
document.write( "y = 4<BR>\n" );
document.write( "So the student got 4 books at 6.50 and 9 - 4 = 5 books at 6.<BR>\n" );
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document.write( "Check:<BR>\n" );
document.write( "4 × 6.50 + 5 × 6 = 56<BR>\n" );
document.write( "26 + 30 = 56 Correct. </SPAN>\n" );
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