document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1079575>Question 1079575</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In a sample of 1000 people,630 said they were most likely to sleep when at home sick with a cold or flu.Determine the proportion of people who sleep when at home sick with a cold?<BR>\n" );
document.write( "b) in order to calculate a confidence interval for p it is neccessary to be able to approximate probability distribution of the number of people who sleep when at home sick with a cold or flu ising a normal distribution.calculate the following np and n(1-p)<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #693880 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=693880\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The point estimate is 630/1000=0.63=p<BR>\n" );
document.write( "np=630<BR>\n" );
document.write( "1-p=0.37<BR>\n" );
document.write( "n(1-p)=370<BR>\n" );
document.write( "the 95% CI is 0.63 +/_ 1.96* sqrt (0.63)(0.37)/1000<BR>\n" );
document.write( "=0.0299 or 0.03<BR>\n" );
document.write( "(0.60, 0.66)<BR>\n" );
document.write( "The variance is np(1-p)=233.1; take the sqrt, multiply by 1.96, and the interval width was 29.92, using 630 as the mean. </SPAN>\n" );
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