document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1079527>Question 1079527</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The personnel office at a large electronics firm regularly schedules job interviews and maintains records of the interviews. From the past records, they have found that the length of a first interview is normally distributed, with mean &#956; = 32 minutes and standard deviation &#963; = 9 minutes. (Round your answers to four decimal places.)<BR>\n" );
document.write( "(a) What is the probability that a first interview will last 40 minutes or longer?<BR>\n" );
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document.write( "(b) Nine first interviews are usually scheduled per day. What is the probability that the average length of time for the nine interviews will be 40 minutes or longer?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #693794 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=693794\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The personnel office at a large electronics firm regularly schedules job interviews and maintains records of the interviews. From the past records, they have found that the length of a first interview is normally distributed, with mean &#956; = 32 minutes and standard deviation &#963; = 9 minutes. (Round your answers to four decimal places.)<BR>\n" );
document.write( "(a) What is the probability that a first interview will last 40 minutes or longer?<BR>\n" );
document.write( "z(40) = (40-32)/9 = 8/9<BR>\n" );
document.write( "P(x >= 40) = P(z >= 8/9) = normalcdf(8/9,100) = 0.1870<BR>\n" );
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document.write( "(b) Nine first interviews are usually scheduled per day. What is the probability that the average length of time for the nine interviews will be 40 minutes or longer?<BR>\n" );
document.write( "z(40) = (40-32)/(9/sqrt(9)) = 8/3<BR>\n" );
document.write( "P(x-bar >= 40) = P(z >= 8/3) = normalcdf(8/3,100) = 0.0038<BR>\n" );
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document.write( "cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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