document.write( "Question 1079517: Adult IQ scores are normally distributed with a mean of 100 and a standard deviation of 15.
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document.write( "find the percentage of adults who have an IQ between 70 and 130 and have and Iq over 130 \n" );
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Algebra.Com's Answer #693786 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! Z=(x-mean)/sd \n" ); document.write( "(130-100)/15=2 and (70-100)/15=-2 \n" ); document.write( "Probability of z between + and -2 is 0.9544 \n" ); document.write( "Probability of z>2 or IQ >130 is 0.0228. From table or calculator. \n" ); document.write( " |