document.write( "Question 1079517: Adult IQ scores are normally distributed with a mean of 100 and a standard deviation of 15.
\n" ); document.write( "find the percentage of adults who have an IQ between 70 and 130 and have and Iq over 130
\n" ); document.write( "

Algebra.Com's Answer #693786 by Boreal(15235)\"\" \"About 
You can put this solution on YOUR website!
Z=(x-mean)/sd
\n" ); document.write( "(130-100)/15=2 and (70-100)/15=-2
\n" ); document.write( "Probability of z between + and -2 is 0.9544
\n" ); document.write( "Probability of z>2 or IQ >130 is 0.0228. From table or calculator.
\n" ); document.write( "
\n" );