document.write( "Question 1079454: how would you find the partial decomposition of \"+%2810x%2B2%29%2F%28%28x%2B2%29%28x-4%29%29+\"\r
\n" ); document.write( "\n" ); document.write( "would you factor the denominator and is it linear A/ax+b?
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Algebra.Com's Answer #693744 by Boreal(15235)\"\" \"About 
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A/(x+2) + B/(x-4)=10x+2/(x+2)(x-4)
\n" ); document.write( "multiply through by (x+2)(x-4)
\n" ); document.write( "A(x-4)+B(x-2)=10x+2
\n" ); document.write( "Ax-4A+Bx-2B=10x+2
\n" ); document.write( "x(A+B)=10x
\n" ); document.write( "-4A-2B=2, or 4A-2B=-2
\n" ); document.write( "A+B=10, so B=10-A
\n" ); document.write( "4A-20+2A=-2
\n" ); document.write( "6A=18
\n" ); document.write( "A=3
\n" ); document.write( "B=7
\n" ); document.write( "It is 3/(x+2) + 7/(x-4)
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