document.write( "Question 1079454: how would you find the partial decomposition of \r
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document.write( "would you factor the denominator and is it linear A/ax+b? \n" );
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Algebra.Com's Answer #693744 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! A/(x+2) + B/(x-4)=10x+2/(x+2)(x-4) \n" ); document.write( "multiply through by (x+2)(x-4) \n" ); document.write( "A(x-4)+B(x-2)=10x+2 \n" ); document.write( "Ax-4A+Bx-2B=10x+2 \n" ); document.write( "x(A+B)=10x \n" ); document.write( "-4A-2B=2, or 4A-2B=-2 \n" ); document.write( "A+B=10, so B=10-A \n" ); document.write( "4A-20+2A=-2 \n" ); document.write( "6A=18 \n" ); document.write( "A=3 \n" ); document.write( "B=7 \n" ); document.write( "It is 3/(x+2) + 7/(x-4) \n" ); document.write( " |