document.write( "Question 1079460: solve for x:[(e^2) . ((e^x)^2)]/ (e^3x) = 2^(x-1) \n" ); document.write( "
Algebra.Com's Answer #693742 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( " solve for x:\r
\n" ); document.write( "\n" ); document.write( "\"%28%28e%5E2%29+%2A%28%28e%5Ex%29%5E2%29%29%2F+%28e%5E%283x%29%29+=+2%5E%28x-1%29+\"\r
\n" ); document.write( "\n" ); document.write( "\"%28e%5E2+%2Ae%5E%282x%29%29%2F+%28e%5E%283x%29%29+=+2%5E%28x-1%29+\"\r
\n" ); document.write( "\n" ); document.write( "\"%28e%5E%282%2B2x%29%29%2F+%28e%5E%283x%29%29+=+2%5E%28x-1%29+\"\r
\n" ); document.write( "\n" ); document.write( "\"e%5E%28%282%2B2x-3x%29%29=+2%5E%28x-1%29+\"\r
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\n" ); document.write( "\n" ); document.write( "\"e%5E%282-x%29=+2%5E%28x-1%29+\"\r
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\n" ); document.write( "\n" ); document.write( "\"log%28e%5E%282-x%29%29=+log%282%5E%28x-1%29+%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"%282-x%29log%28e%29=+%28x-1%29log%282+%29\"........\"log%28e%29=1\"\r
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\n" ); document.write( "\n" ); document.write( "\"2-x=+x%2Alog%282+%29-log%282+%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"-x-+x%2Alog%282+%29=-log%282+%29-2\".... both sides multiply by\"+-1\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%2Bx%2Alog%282+%29=log%282+%29%2B2\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%281%2Blog%282+%29%29=log%282+%29%2B2\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=%28log%282+%29%2B2%29%2F%281%2Blog%282+%29%29\"\r
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