document.write( "Question 521871: The sum of two numbers is five times their difference. If one number exceeds the other by 7, find the numbers. \n" ); document.write( "

Algebra.Com's Answer #693716 by ssm@123(2) $\"\"$ $\"About$

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let the first number be - x
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\n" ); document.write( "let the second number be - x+7
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\n" ); document.write( "the sum of the 2 numbers is - 5(x+(x+7))
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\n" ); document.write( "required equation -
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\n" ); document.write( " x+(x+7) = 5*(x-(x+7)
\n" ); document.write( " x+x+7 = 5*(x-x+7)
\n" ); document.write( " 2x+7 = 5x-5x+35
\n" ); document.write( " 2x+5x-5x = 35-7
\n" ); document.write( " 7x-5x = 28
\n" ); document.write( " 2x = 28
\n" ); document.write( " x = 28/2
\n" ); document.write( " x = 14\r
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\n" ); document.write( "So, the first number = x = 14
\n" ); document.write( " the second number = x+7 = 14+7
\n" ); document.write( " = 21
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\n" ); document.write( "Therefore, the numbers are 7 and 21
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\n" ); document.write( "SOLVED BY -
\n" ); document.write( " SRAVYA SRI \n" ); document.write( "

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