document.write( "Question 1079274: A 1/4 -mile track for racing stock cars consists
\n" ); document.write( "of two semicircles connected by parallel straightaway. In order to provide sufficient room for pit crews,
\n" ); document.write( "emergency vehicles, and spectator parking, the track must enclose an area of 100,000 square feet. Find the length of the
\n" ); document.write( "straightaways and the diameter of the semicircles to the nearest foot.\r
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Algebra.Com's Answer #693668 by josgarithmetic(39617)\"\" \"About 
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Perimeter in feet, \"%281%2F4%29mile%2A5280%28feet%2Fmile%29=1320%2Afeet\"\r
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\n" ); document.write( "\n" ); document.write( "x, rectangular dimension capped with each semicircle part
\n" ); document.write( "y, rectangular dimension not capped with the semicircle part\r
\n" ); document.write( "\n" ); document.write( "radius of each semicircle is \"x%2F2\".\r
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\n" ); document.write( "\n" ); document.write( "Accounting for perimeter and area and simplifying,\r
\n" ); document.write( "\n" ); document.write( "\"system%28pi%2Ax%2B2y=1320%2C4xy%2Bpi%2Ax%5E2=400000%29\"
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\n" ); document.write( "\n" ); document.write( "Solving for y and substituting, and then simplifying,...
\n" ); document.write( "\"pi%2Ax%5E2-2640x%2B40000=0\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=198\", diameter of semicircle parts, in feet
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\n" ); document.write( "\"y=349\", each straight-way part
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