document.write( "Question 1079187: If x varies inversely as y and y varies directly as z what is the relationship between x and z \n" ); document.write( "
Algebra.Com's Answer #693543 by Theo(13342)\"\" \"About 
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x varies inversely as y leads to x = k/y\r
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\n" ); document.write( "\n" ); document.write( "y varies directly as z leads to y = kz.\r
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\n" ); document.write( "\n" ); document.write( "replacing y with kz in x = k/y leads to x = k/(kz)\r
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\n" ); document.write( "\n" ); document.write( "simplifying that leads to x = 1/z\r
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\n" ); document.write( "\n" ); document.write( "looks like z is the reciprocal of x.\r
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\n" ); document.write( "\n" ); document.write( "this assumes that k is the same in both equations, as i believe it needs to be in order for the equations to work.\r
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\n" ); document.write( "\n" ); document.write( "for example:\r
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\n" ); document.write( "\n" ); document.write( "let x = 10 and y = 5.\r
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\n" ); document.write( "\n" ); document.write( "we can solve for k in the first equation.\r
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\n" ); document.write( "\n" ); document.write( "we get x = k/y becomes 10 = k/5.\r
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\n" ); document.write( "\n" ); document.write( "solve for k to get k = 50.\r
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\n" ); document.write( "\n" ); document.write( "now replace y with 5 and k with 50 in the second equation.\r
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\n" ); document.write( "\n" ); document.write( "we get y = kz becomes 5 = 50 * z\r
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\n" ); document.write( "\n" ); document.write( "solve for z to get z = 5/50 = 1/10\r
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\n" ); document.write( "\n" ); document.write( "x was equal to 10
\n" ); document.write( "z is equal to 1/10\r
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\n" ); document.write( "\n" ); document.write( "z is the reciprocal of x.\r
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\n" ); document.write( "\n" ); document.write( "that's what i think is going on.
\n" ); document.write( "can't swear to it because i've never seen one like this before.
\n" ); document.write( "it does, however, seem reasonable.\r
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