document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1079140>Question 1079140</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a sprinkler located in the center of a circular enclosure of grass fans out and waters at an angle of 90 degrees. what is the area of the grass that is watered if the diameter of the enclosure is 50 ft </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #693504 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=693504\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The area is 1/4 of the area of the circle, which itself is pi*25^2 ft^2, the 25 the radius.<BR>\n" );
document.write( "(1/4)*625 pi=156.25 pi<BR>\n" );
document.write( "=490.87 ft^2. </SPAN>\n" );
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