document.write( "Question 13808: the perimeter of a rectangle is 44cm. The length is 2cm more than three times the width. Find the dimensions of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #6935 by problems_solved(3)![]() ![]() ![]() You can put this solution on YOUR website! dear friend \n" ); document.write( "let us consider the width as x \n" ); document.write( "then the length is 3x+2 \n" ); document.write( "so perimeter of a rectangle is 2*(length+width) \n" ); document.write( " =2*(x+3x+2) \n" ); document.write( " =8x+4 \n" ); document.write( " 8x+4 =44 \n" ); document.write( "solving x =5 \n" ); document.write( "so width=5 cm & length=17cm \n" ); document.write( " \n" ); document.write( " |