document.write( "Question 1079015: Find the equation of the circle that passes through the origin and (2,4); tangent to the line 3x - 2y = 12. \n" ); document.write( "
Algebra.Com's Answer #693473 by ikleyn(52855) You can put this solution on YOUR website! . \n" ); document.write( "Find the equation of the circle that passes through the origin and (2,4); tangent to the line 3x - 2y = 12. \n" ); document.write( "~~~~~~~~~~~~~~~~~~~~~~~\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( "According to the condition, the circle passes through the points (0,0) and (2,4).\r\n" ); document.write( "Therefore, its center lies on the perpendicular bisector of the segment connecting these points.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " Now, the idea on how to solve the problem is to find the point on the perpendicular bisector EQUIDISTANT from the given points \r\n" ); document.write( " AND from the given straight line.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "The midpoint between (0,0) and (2,4) is the point (1,2).\r\n" ); document.write( "\r\n" ); document.write( "The slope of the segment connecting (0,0) and (2,4) is\r \n" ); document.write( "\n" ); document.write( "Writing of \"josgarithmetic\" on this problem is wrong and irrelevant.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |