document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1079078>Question 1079078</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A soda can that has a temperature of<BR>\n" );
document.write( "80 degrees<BR>\n" );
document.write( "F is put into a cooler containing ice (<BR>\n" );
document.write( "32degrees<BR>\n" );
document.write( "F). The temperature of the soda can<BR>\n" );
document.write( "after t minutes can be modeled by f(t)=32+48(0.9)^t<BR>\n" );
document.write( "How long will it take to cool the can of soda down to 50 degrees?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #693438 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=693438\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 50=32+48*(0.9)^t<BR>\n" );
document.write( "18=48*(0.9)^t<BR>\n" );
document.write( "(3/8)=0.9^t<BR>\n" );
document.write( "ln(3/8)=t ln (0.9)<BR>\n" );
document.write( "divide and round at the end<BR>\n" );
document.write( "t=9.31 hours<BR>\n" );
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