document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1078969>Question 1078969</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Events A and B are independent.  P(A) = 11/20, P (A or B) =73/100 P(B)=?<BR>\n" );
document.write( "A)2/5, B)167/200, C)7/20, D) 1/5<BR>\n" );
document.write( "I did 73/100=11/20 + p(B) with P(b)=9/50??? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #693431 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=693431\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> P (a or b)=p(a)+p(b)-p(both)<BR>\n" );
document.write( "73/100=55/100+p(b)-(.55*P(b))<BR>\n" );
document.write( "9/50=0.45 p(b)=0.18<BR>\n" );
document.write( "p(b)=2/5 or .40.<BR>\n" );
document.write( "The important part here is that they are said to be independent.  That gives the joint probability part.  If they were mutually exclusive, 9/50 would work.<BR>\n" );
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