document.write( "Question 1079041: Please help me solve this
\n" ); document.write( "Consider the function f(x) = x3 + px + q.
\n" ); document.write( "(a) Determine the values of p and q if f(x) has a stationary point at (−2,3).
\n" ); document.write( "(b) Show, using calculus, that there is a second stationary point at (2,−29), and classify both
\n" ); document.write( "stationary points.
\n" ); document.write( "(c) Determine f′′(x) and hence show that there is a non-stationary point of inflection and determine its coordinates.
\n" ); document.write( "(d) For what values of k would the equation f(x) = k have 3 distinct solutions. Give reasons for your answer.
\n" ); document.write( "(Hint: Sketch the graph of y = f(x)
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Algebra.Com's Answer #693420 by Boreal(15235)\"\" \"About 
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Derivative of the function is 3x^2+p
\n" ); document.write( "Set that equal to 0 and x^2=-p/3 at the stationary point.
\n" ); document.write( "F(-2)=-8-2p+q=3
\n" ); document.write( "q-2p=11
\n" ); document.write( "x^2=-p/3, 4=-p/3 and p=-12;
\n" ); document.write( "Therefore q=-13
\n" ); document.write( "x^3-12x-13
\n" ); document.write( "3x^2-12=0
\n" ); document.write( "x=+/-2
\n" ); document.write( "when x=2, f(2)=8-24-13=-29, so (2,-29) is a point.
\n" ); document.write( "\"graph%28300%2C300%2C-10%2C10%2C-35%2C25%2Cx%5E3-12x-13%29\"
\n" ); document.write( "The second derivative is 6x.
\n" ); document.write( "When x<0, the second derivative is negative and there is a maximum.
\n" ); document.write( "When x>0, it is positive and there is a minimum.
\n" ); document.write( "the inflection point occurs at (0, -13), for there the second derivative changes sign.\r
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