document.write( "Question 1079041: Please help me solve this
\n" );
document.write( "Consider the function f(x) = x3 + px + q.
\n" );
document.write( "(a) Determine the values of p and q if f(x) has a stationary point at (−2,3).
\n" );
document.write( "(b) Show, using calculus, that there is a second stationary point at (2,−29), and classify both
\n" );
document.write( "stationary points.
\n" );
document.write( "(c) Determine f′′(x) and hence show that there is a non-stationary point of inflection and determine its coordinates.
\n" );
document.write( "(d) For what values of k would the equation f(x) = k have 3 distinct solutions. Give reasons for your answer.
\n" );
document.write( "(Hint: Sketch the graph of y = f(x) \n" );
document.write( "
Algebra.Com's Answer #693420 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! Derivative of the function is 3x^2+p \n" ); document.write( "Set that equal to 0 and x^2=-p/3 at the stationary point. \n" ); document.write( "F(-2)=-8-2p+q=3 \n" ); document.write( "q-2p=11 \n" ); document.write( "x^2=-p/3, 4=-p/3 and p=-12; \n" ); document.write( "Therefore q=-13 \n" ); document.write( "x^3-12x-13 \n" ); document.write( "3x^2-12=0 \n" ); document.write( "x=+/-2 \n" ); document.write( "when x=2, f(2)=8-24-13=-29, so (2,-29) is a point. \n" ); document.write( " \n" ); document.write( "The second derivative is 6x. \n" ); document.write( "When x<0, the second derivative is negative and there is a maximum. \n" ); document.write( "When x>0, it is positive and there is a minimum. \n" ); document.write( "the inflection point occurs at (0, -13), for there the second derivative changes sign.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |