document.write( "Question 1079056: 1.Sketch the graph of y=-x2-2x+3
\n" ); document.write( "2.Sketch the graph of y=-x2+2x-2
\n" ); document.write( "3.Find the equation for the linear function that is parallel to f(x)=3/2x-3 through (4,-1)
\n" ); document.write( "4.Find the equation of the line that is perpendicular to the equation f(x)=2.5x-0.5 through (-4,2)
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Algebra.Com's Answer #693414 by Boreal(15235)\"\" \"About 
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x^2-2x+3
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\n" ); document.write( "-x^2+2x-2
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\n" ); document.write( "parallel lines have the same slope
\n" ); document.write( "point slope formula where y-y1=m(x-x1), m slope, (x1,y1) a point. Watch the signs.
\n" ); document.write( "y+1=(3/2)(x-4) and y=(3/2)x-7
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\n" ); document.write( "Perpendicular lines have a negative reciprocal slope
\n" ); document.write( "slope of the given line is 5/2, so line perpendicular has a slope of -2/5
\n" ); document.write( "y-2=(-2/5)(x+4)
\n" ); document.write( "y=(-2/5)x+(2/5)
\n" ); document.write( "\"graph%28300%2C300%2C-10%2C10%2C-10%2C10%2C2.5x-0.5%2C%28-2%2F5%29x%2B%282%2F5%29%29\"\r
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