document.write( "Question 1079033: The Population of Nowheresville increased by 4% per year for the last 3 years. If the population 3 years ago was 17,350, what is the population today? Round to the nearest whole number.\r
\n" ); document.write( "\n" ); document.write( "Also, the same problem, but what if the population decreased by 4% for 3 years, with the starting population of 17, 350.\r
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Algebra.Com's Answer #693396 by natolino_2017(77)\"\" \"About 
You can put this solution on YOUR website!
First Problem.\r
\n" ); document.write( "\n" ); document.write( "Let Pn: the population in Nowheresville after n years.\r
\n" ); document.write( "\n" ); document.write( "Pn = 17,350*(1,04)^n\r
\n" ); document.write( "\n" ); document.write( "So P3 = 17,350*(1.04)^3 = 19,516.\r
\n" ); document.write( "\n" ); document.write( "Second Problem.\r
\n" ); document.write( "\n" ); document.write( "Let Pn: the population in Nowheresville after n years.\r
\n" ); document.write( "\n" ); document.write( "Pn = 17,350*(0.96)^n\r
\n" ); document.write( "\n" ); document.write( "So P3 = 17,350*(0.96)^3 = 15,350.\r
\n" ); document.write( "\n" ); document.write( "For every problem, we can use a geometric progession, as the total increasing (or decreasing) is larger (smaller) every year.\r
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