document.write( "Question 1078526: The difference in ages between a boy and his younger brother is 6years.the younger brother is6 years older than his sister.the sum of ages if the younger brother and his sister is 30.how old are the three children?
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Algebra.Com's Answer #693355 by ankor@dixie-net.com(22740)\"\" \"About 
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let b = the boy's age
\n" ); document.write( "let y = the younger brother's age
\n" ); document.write( "let s = the sister's age
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\n" ); document.write( "write an equation for each statement, arrange to have b and s in terms of y
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\n" ); document.write( "The difference in ages between a boy and his younger brother is 6 years.
\n" ); document.write( "b - y = 6
\n" ); document.write( "b = y + 6
\n" ); document.write( "the younger brother is 6 years older than his sister.
\n" ); document.write( "y = s + 6
\n" ); document.write( "s = y - 6
\n" ); document.write( "the sum of ages if the younger brother and his sister is 30.
\n" ); document.write( "b + y + s = 30
\n" ); document.write( "replace b with (y+6), replace s with (y-6)
\n" ); document.write( "(y+6) + y + (y-6) = 30
\n" ); document.write( "combine like terms
\n" ); document.write( "3y = 30
\n" ); document.write( "y = 30/3
\n" ); document.write( "y = 10 yrs is younger bro's age
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\n" ); document.write( "how old are the three children?
\n" ); document.write( "b = 10 + 6 = 16 yrs is the boy's age
\n" ); document.write( "and
\n" ); document.write( "s = 10 - 6 = 4 yrs is the sister's age
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\n" ); document.write( "You can confirm this by finding the sum of the 3 ages \n" ); document.write( "
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