document.write( "Question 1078914: tgx + ctgx = -2 \n" ); document.write( "
Algebra.Com's Answer #693293 by ikleyn(52866)\"\" \"About 
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document.write( "Let y = tg(x) be the new variable.\r\n" );
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document.write( "Then the given equation takes the form  \r\n" );
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document.write( "\"y+%2B+1%2Fy\" = -2.\r\n" );
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document.write( "Multiply by y both sides. You will get\r\n" );
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document.write( "\"y%5E2+%2B+1\" = -2y,   or\r\n" );
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document.write( "\"y%5E2+%2B+2y+%2B+1\" = 0,\r\n" );
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document.write( "\"%28y%2B1%29%5E2\" = 0  --->  y+1 = 0.\r\n" );
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document.write( "Hence, tg(x) + 1 = 0  --->  tg(x) = -1  --->  x = \"3pi%2F4\"  and/or  x = \"7pi%2F4\".\r\n" );
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document.write( "Answer.  There are 2 solutions:  x = \"3pi%2F4\"  and/or  x = \"7pi%2F4\".\r\n" );
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