document.write( "Question 1078849: A contractor agrees to lay a road 3000 m long in 30 days. 50 men are employed and they work for 8 hours per day. After 20 working days, he finds that only 1200 m of the road is completed. How many more men does he need to employ in order to finish the project on time if each man now works 10 hours a day? \n" ); document.write( "
Algebra.Com's Answer #693257 by ankor@dixie-net.com(22740)\"\" \"About 
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A contractor agrees to lay a road 3000 m long in 30 days.
\n" ); document.write( " 50 men are employed and they work for 8 hours per day.
\n" ); document.write( " After 20 working days, he finds that only 1200 m of the road is completed.
\n" ); document.write( " How many more men does he need to employ in order to finish the project on time if each man now works 10 hours a day?
\n" ); document.write( ":
\n" ); document.write( "Find how many man-hrs needed to complete 1200 meters
\n" ); document.write( "50 * 8 * 20 = 8000 man-hrs
\n" ); document.write( "Find how many man-hrs per meter
\n" ); document.write( "8000/1200 = 6.67 man-hr per meter
\n" ); document.write( "then find how many for the remaining 1800 meters
\n" ); document.write( "6.67 * 1800 = 12000 man-hr required to complete the job
\n" ); document.write( ":
\n" ); document.write( "let m = the additional men required working 10 hrs a day for the 10 days left on the contract
\n" ); document.write( "(50+m) * 10 * 10 = 12000
\n" ); document.write( "100(50+m) = 12000
\n" ); document.write( "50 + m = 12000/100
\n" ); document.write( "50 + m = 120
\n" ); document.write( "m = 120 - 50
\n" ); document.write( "m = 70 additional men required
\n" ); document.write( " \n" ); document.write( "
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