document.write( "Question 1078733: Use the distance formula to find the equation of a parabola with a focus at (0, 20) and a directrix at the x-axis, y = -10.\r
\n" ); document.write( "\n" ); document.write( "y = (1/30)x^2 + 10
\n" ); document.write( "y = (1/60)x^2 + 5
\n" ); document.write( "y = (1/60)x^2 + 10
\n" ); document.write( "y = (1/30)x^2 + 5
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Algebra.Com's Answer #693165 by Boreal(15235)\"\" \"About 
You can put this solution on YOUR website!
the vertex is at (0,5), half way between the focus and the directrix.
\n" ); document.write( "half the distance is 15
\n" ); document.write( "This is a y=x^2 type of parabola
\n" ); document.write( "(x)^2=4p(y-5)
\n" ); document.write( "x^2=60p(y-5)
\n" ); document.write( "y=(x^2/60)+5
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