document.write( "Question 1078771: Log10x+lg4x=2 find value of x \n" ); document.write( "

Algebra.Com's Answer #693161 by stanbon(75887) $\"\"$ $\"About$

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Log10x+log4x=2 find value of x
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\n" ); document.write( "log[10x*4x] = 2
\n" ); document.write( "log[40x^2] = 2
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\n" ); document.write( "40x^2 = 10^2
\n" ); document.write( "x^2 = 100/40
\n" ); document.write( "x^2 = 2.5
\n" ); document.write( "x = +/-sqrt(2.5)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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