document.write( "Question 1078656: An angle measures 46° more than the measure of a complementary angle. What is the measure of each angle? Thanks
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Algebra.Com's Answer #693051 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "Two angles are \"complementary\" when they add up to \"90\" degrees.\r
\n" ); document.write( "\n" ); document.write( "let's angle be \"alpha\" and its complementary angle \"beta\"\r
\n" ); document.write( "\n" ); document.write( "\"alpha%2Bbeta=90\"=>\"alpha=90-beta\"....eq.1\r
\n" ); document.write( "\n" ); document.write( "given:
\n" ); document.write( "an angle measures \"46\"° \"more\" than the measure of a complementary angle\r
\n" ); document.write( "\n" ); document.write( "so, \"alpha\" measures \"46\"° \"more\" than \"beta\"=>\r
\n" ); document.write( "\n" ); document.write( "\"alpha=beta%2B46\"........eq.2\r
\n" ); document.write( "\n" ); document.write( "from eq.1 and eq.2 we have\r
\n" ); document.write( "\n" ); document.write( "\"90-beta=beta%2B46\"\r
\n" ); document.write( "\n" ); document.write( "\"90-46=beta%2Bbeta\"\r
\n" ); document.write( "\n" ); document.write( "\"44=2beta\"\r
\n" ); document.write( "\n" ); document.write( "\"44%2F2=beta\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28beta=22%29\"° \r
\n" ); document.write( "\n" ); document.write( "find \"alpha\"\r
\n" ); document.write( "\n" ); document.write( "\"alpha=90-beta\"....eq.1\r
\n" ); document.write( "\n" ); document.write( "\"alpha=90-22\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28alpha=68%29\"° \r
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