document.write( "Question 95147: Ten percent of the reds are added to twenty percent of the blues, and the total is 24.Yet the product of the nunber of reds and 3 exceeds the number of blues by 20.How many are red and how many are blue? \n" ); document.write( "
Algebra.Com's Answer #69304 by ptaylor(2198)![]() ![]() You can put this solution on YOUR website! Let x=number of reds \n" ); document.write( "And y=number of blues \n" ); document.write( "Now we are told that:\r \n" ); document.write( "\n" ); document.write( "0.10x+0.20y=24-----------------------------eq1\r \n" ); document.write( "\n" ); document.write( "We are also told that: \n" ); document.write( "x*3=y+20 or\r \n" ); document.write( "\n" ); document.write( "3x=y+20 subtract 20 from both sides \n" ); document.write( "y=3x-20 -----------------------------------eq2\r \n" ); document.write( "\n" ); document.write( "substitute y=3x-20 from eq2 into eq1\r \n" ); document.write( "\n" ); document.write( "0.10x+0.20(3x-20)=24 get rid of parens\r \n" ); document.write( "\n" ); document.write( "0.10x+0.60x-4=24 add 4 to both sides\r \n" ); document.write( "\n" ); document.write( "0.10x+0.60x-4+4=24+4 collect like terms\r \n" ); document.write( "\n" ); document.write( "0.70x=28 divide both sides by 0.70 \n" ); document.write( "x=40---------------------------------------number of reds\r \n" ); document.write( "\n" ); document.write( "substitute x=40 into eq2:\r \n" ); document.write( "\n" ); document.write( "y=3*40-20 \n" ); document.write( "y=120-20=100-------------------------------number of blue\r \n" ); document.write( "\n" ); document.write( "CK\r \n" ); document.write( "\n" ); document.write( "0.10*40+0.20*100=24 \n" ); document.write( "4+20=24 \n" ); document.write( "24=24 \n" ); document.write( "also\r \n" ); document.write( "\n" ); document.write( "3*40 exceeds 100 by 20\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Hope this helps--ptaylor\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |