document.write( "Question 1078578: What is the slope for the line tangent to the circle x^2 + y^2 = 8 at the point (2, -2)? \n" ); document.write( "

Algebra.Com's Answer #692998 by ikleyn(52781) $\"\"$ $\"About$

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\n" ); document.write( "The radius-vector from the center to the point (2,-2) has the slope $\"%28-2%29%2F2\"$ = -1.\r
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\n" ); document.write( "\n" ); document.write( "The tangent line to the circle at the tangent point is perpendicular to the radius.\r
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\n" ); document.write( "\n" ); document.write( "Hence, the tangent line has the slope 1, reciprocal and opposite by the sign to the slope of the radius.\r
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\n" ); document.write( "\n" ); document.write( "Answer. 1.\r
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