document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1078560>Question 1078560</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How much water should be added to 6 liters of 30% acid solution to dilute it to a 12%soution </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #692992 by </B><A HREF=/tutors/aboutme.mpl?userid=natolino_2017><B>natolino_2017(77)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=natolino_2017><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=692992\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let W:Water on the initial solution<BR>\n" );
document.write( "    A:Acid on the initial solutiom.<BR>\n" );
document.write( "    X:Water need to be added.\r<BR>\n" );
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document.write( "1) A+W=6<BR>\n" );
document.write( "2) A/(A+W)=30%<BR>\n" );
document.write( "3) A/(A+W+X)=12%\r<BR>\n" );
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document.write( "Using 1) and 2) \r<BR>\n" );
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document.write( "A/6=30%, solving for A, A=1,8 liters.\r<BR>\n" );
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document.write( "So in 3) 1,8/(6+x)=12%, solving for x, 6+x=15, x=9 liters.\r<BR>\n" );
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document.write( "Answer: you must add 9 liters of water in order to make the solution of 12%.\r<BR>\n" );
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document.write( "@natolino_<BR>\n" );
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