document.write( "Question 1078560: How much water should be added to 6 liters of 30% acid solution to dilute it to a 12%soution \n" ); document.write( "
Algebra.Com's Answer #692985 by Boreal(15235)\"\" \"About 
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x=amount of water in liters
\n" ); document.write( "6(.30)+x(0)=(6+x)(.12), pure acid amount
\n" ); document.write( "1.8=0.72+.12x
\n" ); document.write( ".12x=1.08
\n" ); document.write( "x=9 liters
\n" ); document.write( "The total solution will be 15 liters
\n" ); document.write( "going from 6 to 15 is an increase of 2.5
\n" ); document.write( "the reciprocal is 0.4, and that times 30%=12% check.
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