document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1078547>Question 1078547</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The area of a rectangle is 64cm squared. What are the dimensions if the perimeter is a minimum? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #692983 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=692983\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> length is x<BR>\n" );
document.write( "width is y<BR>\n" );
document.write( "xy=64 cm^2<BR>\n" );
document.write( "y=64/x<BR>\n" );
document.write( "perimeter is 2x+2y=2x+128/x<BR>\n" );
document.write( "That has to be a minimum<BR>\n" );
document.write( "derivative of that is 2-128/x^2<BR>\n" );
document.write( "Set that equal to 0<BR>\n" );
document.write( "128/x^2=2<BR>\n" );
document.write( "2x^2=128<BR>\n" );
document.write( "x=8 cm<BR>\n" );
document.write( "y=8 cm<BR>\n" );
document.write( "It is a square, and the perimeter is a minimum of 32 cm.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );