document.write( "Question 1078546: Find the equation of the circle that passes through (-1,1) and with centre at the point of intersection of x + 3y + 7 = 0 and 3x - 2y - 12 = 0. \n" ); document.write( "
Algebra.Com's Answer #692974 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( " Find the equation of the circle that passes through (\"-1\",\"1\") and with center at the point of intersection of \"x+%2B+3y+%2B+7+=+0\" and \"3x+-+2y+-+12+=+0\".\r
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\n" ); document.write( "\n" ); document.write( "equation of the circle: \r
\n" ); document.write( "\n" ); document.write( "\"%28x-h%29%5E2%2B%28y-k%29%5E2=r%5E2+where+%7B%7B%7Bh\" and \"k\" are \"x\" and \"y\" coordinates of center, and \"r\" is radius\r
\n" ); document.write( "\n" ); document.write( "use \"x+%2B+3y+%2B+7+=+0\" and \"3x+-+2y+-+12+=+0\" to find \"x\" and \"y\" coordinates of center\r
\n" ); document.write( "\n" ); document.write( "\"x+%2B+3y+%2B+7+=+0\"...........solve for \"x\"
\n" ); document.write( "\"x+=-3y-7\"............substitute in equation\r
\n" ); document.write( "\n" ); document.write( "\"3%28-3y-7%29+-+2y+-+12+=+0\"\r
\n" ); document.write( "\n" ); document.write( "\"-9y+-21-+2y+-+12+=+0\"\r
\n" ); document.write( "\n" ); document.write( "\"-11y+-33+=+0\"
\n" ); document.write( "\"-11y+=+33\"
\n" ); document.write( "\"y+=+33%2F-11\"
\n" ); document.write( "\"y+=+-3\"\r
\n" ); document.write( "\n" ); document.write( "find \"x%7D%7D%0D%0A%0D%0A%7B%7B%7Bx+=-3%28-3%29-7\"
\n" ); document.write( "\"x+=9-7\"
\n" ); document.write( "\"x+=2\"\r
\n" ); document.write( "\n" ); document.write( "so, \"x=h\" and \"y=k\" coordinates of center are: \"2\" and \"-3\"\r
\n" ); document.write( "\n" ); document.write( "and equation of your circle (so far) is:
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\n" ); document.write( "\n" ); document.write( "use given point (\"-1\",\"1\") and substitute its \"x\" and \"y\" coordinates\r
\n" ); document.write( "\n" ); document.write( "\"%28-1-2%29%5E2%2B%281%2B3%29%5E2=r%5E2\"
\n" ); document.write( "\"%28-3%29%5E2%2B%284%29%5E2=r%5E2\"
\n" ); document.write( "\"9%2B16=r%5E2\"
\n" ); document.write( "\"25=r%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"%28x-2%29%5E2%2B%28y%2B3%29%5E2=25+\" ->equation of your circle\r
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