document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1078458>Question 1078458</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A tank holds 80 liters of chemical solution. Currently, the solution has a strength of 30% How much of this solution must be drained and replace with a 70% solution to get a strength of 40% </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #692910 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=692910\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> amount drained and replaced=x<BR>\n" );
document.write( "(80-x)0.30x+.70x=(80)*0.4<BR>\n" );
document.write( "24-.3x+.70x=32<BR>\n" );
document.write( ".4x+24=32<BR>\n" );
document.write( ".4x=8<BR>\n" );
document.write( "x=20 liters<BR>\n" );
document.write( "Check<BR>\n" );
document.write( "Start with 80*.30=24 liters of pure.<BR>\n" );
document.write( "Want 80 liters of .40=32 liters of pure<BR>\n" );
document.write( "For every 10 liters of 30% removed and replaced with 70%, 4 extra liters of pure are added.<BR>\n" );
document.write( "Need 20 liters of 30% removed and replaced with 70%.<BR>\n" );
document.write( "That will be 60 liters*.30=18 liters and 20 liters of 70% = 14 liters.  Total 32 liters. </SPAN>\n" );
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