document.write( "Question 95210: A rectangle is three times as long as it is wide. If its length and width are both decreased by 2cm, its area is decreased by 36 cm sqaure. Find its original dimensions. \n" ); document.write( "

Algebra.Com's Answer #69291 by edjones(8007) $\"\"$ $\"About$

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L*W=A
\n" ); document.write( "L=3W
\n" ); document.write( " $\"A=3w%2Aw=3w%5E2\"$
\n" ); document.write( "(3w-2)*(w-2)=A-36
\n" ); document.write( " $\"3w%5E2-8w%2B4=3w%5E2-36\"$
\n" ); document.write( "subtract $\"3w%5E2\"$ from both sides. -8w+4=-36
\n" ); document.write( "multiply -1 times both sides. 8w-4=36
\n" ); document.write( "add 4 to both sides. 8w=40
\n" ); document.write( "divide 8 into both sides. w=5 cm Ans.
\n" ); document.write( "Check 5*15=75 (original area)
\n" ); document.write( "3*13=39 (area after -2cm subtacted from each side)
\n" ); document.write( "75-39=36 cm sq. (difference in the 2 areas)
\n" ); document.write( "right on!
\n" ); document.write( "EdJones \n" ); document.write( "

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