document.write( "Question 1078264: Account A and B each start out with $500. If Account A earns $50 each year and Account B earns 5% of its value each year, after how many years will Account B have more money than Account A? If necessary, round your answer to the nearest year.
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\n" ); document.write( "After about
\n" ); document.write( " (blank) years Account B will have more money than Account A.
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Algebra.Com's Answer #692873 by ankor@dixie-net.com(22740)\"\" \"About 
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Account A and B each start out with $500.
\n" ); document.write( " If Account A earns $50 each year and Account B earns 5% of its value each year, after how many years will Account B have more money than Account A?
\n" ); document.write( " If necessary, round your answer to the nearest year.
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\n" ); document.write( "Let y = no. years for this to be true
\n" ); document.write( "500*1.05^y > 500 + 50y
\n" ); document.write( "1.05^y > \"%28500%2B50y%29%2F500\"
\n" ); document.write( "1.05^y > 1 + .1y
\n" ); document.write( "1.05^y -.1y - 1 = 0 Graphically
\n" ); document.write( "\"+graph%28+300%2C+200%2C+-10%2C+50%2C+-2%2C+4%2C+1.05%5Ex-.1x-1%29+\"
\n" ); document.write( "\"After about\" 27 yrs \"years Account B will have more money than Account A.\"
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\n" ); document.write( "Check this on the your calc
\n" ); document.write( "Account A: 27(50) + 500 = $1850
\n" ); document.write( "Account B: 500(1.05^27) = $1866.73
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