document.write( "Question 1078264: Account A and B each start out with $500. If Account A earns $50 each year and Account B earns 5% of its value each year, after how many years will Account B have more money than Account A? If necessary, round your answer to the nearest year.
\n" );
document.write( "
\n" );
document.write( "After about
\n" );
document.write( " (blank) years Account B will have more money than Account A.
\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #692873 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Account A and B each start out with $500. \n" ); document.write( " If Account A earns $50 each year and Account B earns 5% of its value each year, after how many years will Account B have more money than Account A? \n" ); document.write( " If necessary, round your answer to the nearest year. \n" ); document.write( ": \n" ); document.write( "Let y = no. years for this to be true \n" ); document.write( "500*1.05^y > 500 + 50y \n" ); document.write( "1.05^y > \n" ); document.write( "1.05^y > 1 + .1y \n" ); document.write( "1.05^y -.1y - 1 = 0 Graphically \n" ); document.write( " \n" ); document.write( "\"After about\" 27 yrs \"years Account B will have more money than Account A.\" \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check this on the your calc \n" ); document.write( "Account A: 27(50) + 500 = $1850 \n" ); document.write( "Account B: 500(1.05^27) = $1866.73 \n" ); document.write( " |