document.write( "Question 1078362: An urn contains
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document.write( "7
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document.write( " white and
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document.write( "6
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document.write( " green balls. Four balls are randomly drawn from the urn in succession, with replacement. That is, after each draw, the selected ball is returned to the urn. What is the probability that all
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document.write( "4
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document.write( " balls drawn from the urn are white? \n" );
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Algebra.Com's Answer #692857 by natolino_2017(77)![]() ![]() ![]() You can put this solution on YOUR website! P()=P(Pick a white ball)*P(Pick a white ball)*P(Pick a white ball)*P(Pick a white ball).\r \n" ); document.write( "\n" ); document.write( "P(Pick a white ball)= 7/(6+7)=7/13.\r \n" ); document.write( "\n" ); document.write( "P()=(7/13)^4 = 2401/28561 = 0.0841 = 8.41%\r \n" ); document.write( "\n" ); document.write( "*******bonus: if the question switches to without replacement:\r \n" ); document.write( "\n" ); document.write( "P() =P(pick a white ball)* P(pick another white ball) *P(pick another white ball(2)) * P(pick another white ball(3)). \n" ); document.write( "P()= 7/(6+7) * 6/(6+6)* 5/(6+5)* 4/(6+4) = 7/143 = 0.0196 = 1.96%************* \r \n" ); document.write( "\n" ); document.write( "#natolino \n" ); document.write( " |