document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=13737>Question 13737</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how many metric tons of chromiun must be added to 2.50 metric tons of stainless steel to raise the percent chromium from 11% to 18% </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #6928 by </B><A HREF=/tutors/aboutme.mpl?userid=longjonsilver><B>longjonsilver(2297)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=longjonsilver><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=longjonsilver><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=6928\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> questions like these are always about \"BEFORE\" + \"ADDED\" = \"AFTER\"\r<BR>\n" );
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document.write( "BEFORE:<BR>\n" );
document.write( "2.5*0.11 of 11% chromium steel<BR>\n" );
document.write( "x*1.00 of 100% chromium --> this is the \"tricky\" part, realising that the chromium is 100% \r<BR>\n" );
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document.write( "AFTER:<BR>\n" );
document.write( "(2.5+x)*0.18\r<BR>\n" );
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document.write( "so, these 2 are equivalent:<BR>\n" );
document.write( "2.5*0.11 + x = (2.5+x)*0.18\r<BR>\n" );
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document.write( "0.275 + x = 0.45 + 0.18x<BR>\n" );
document.write( "0.275 + 0.82x = 0.45<BR>\n" );
document.write( "0.82x = 0.175<BR>\n" );
document.write( "--> x = 0.21 metric tonnes\r<BR>\n" );
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document.write( "jon.<BR>\n" );
document.write( " </SPAN>\n" );
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