document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1078284>Question 1078284</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A rectangular plot of ground is to be enclosed by a fence then divided down the middle by another fence. If the fence down the middle costs $3 and the rest of the fencing costs $5.  find the dimensions of the plot of the largest possible area that can be fenced for $130 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #692799 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=692799\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A rectangular plot of ground is to be enclosed by a fence then divided down the middle by another fence.<BR>\n" );
document.write( " If the fence down the middle costs $3 and the rest of the fencing costs $5. find the dimensions of the plot of the largest possible area that can be fenced for $130.<BR>\n" );
document.write( ":<BR>\n" );
document.write( "let L = the length of the plot<BR>\n" );
document.write( "let w = the width of the plot<BR>\n" );
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document.write( "5(2L) + 5(2w) + 3w = 130<BR>\n" );
document.write( "10L + 10w + 3w = 130<BR>\n" );
document.write( "10L + 13w = 130<BR>\n" );
document.write( "10L = -13w + 130<BR>\n" );
document.write( "L = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-13%2F10 ALIGN=MIDDLE  ALT=\"-13%2F10\"   DISABLED_style= \"max-width:90%; height:auto;\" >w + 13<BR>\n" );
document.write( "L = -1.3w + 13<BR>\n" );
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document.write( "Area <BR>\n" );
document.write( "A = L * w<BR>\n" );
document.write( "replace L with (-1.3w+13)<BR>\n" );
document.write( "A = (-1.3w + 13)*w =<BR>\n" );
document.write( "A = -1.3w^2 + 13w<BR>\n" );
document.write( "A quadratic equation. Max area occurs on the axis of symmetry (x=-b/2a)<BR>\n" );
document.write( "w = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28-13%29%2F%282%2A-1.3%29 ALIGN=MIDDLE  ALT=\"%28-13%29%2F%282%2A-1.3%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "w = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28-13%29%2F%28-2.6%29 ALIGN=MIDDLE  ALT=\"%28-13%29%2F%28-2.6%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "w = 5 meters is the width for max area<BR>\n" );
document.write( "then<BR>\n" );
document.write( "L = -1.3(5) + 13<BR>\n" );
document.write( "L = -6.5 + 13<BR>\n" );
document.write( "L = 6.5 meters is the length for max area<BR>\n" );
document.write( ":<BR>\n" );
document.write( "Max area = 5 * 6.5 = 32.5 sq meters<BR>\n" );
document.write( "  </SPAN>\n" );
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