document.write( "Question 95094: find the missing endpoint given one endpoint and midpoint
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\n" ); document.write( "endpoint- (4,2) midpoint-(6,0)
\n" ); document.write( "2)
\n" ); document.write( "endpoint- ( -4,1) midpoint-(-1,3)
\n" ); document.write( "3)
\n" ); document.write( "endpoint-(-3,6) midpoint- (-4,4)
\n" ); document.write( "4)
\n" ); document.write( "endpoint-(6,-10) midpoint (-1,2)\r
\n" ); document.write( "\n" ); document.write( "PLEASE PLEASE PLEASE HELP \n" ); document.write( "
Algebra.Com's Answer #69279 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Comment: The coordiinates of a midpoint are always the average of the corresponding coordinates of the endpoints.
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\n" ); document.write( "endpoint- (4,2) midpoint-(6,0)
\n" ); document.write( "Let the endpoint be (x,y)
\n" ); document.write( "(4+x)/2=6 and (2+y)/2=0
\n" ); document.write( "x = 8 and y = -2
\n" ); document.write( "Midpoint is (8,-2)
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\n" ); document.write( "2)
\n" ); document.write( "endpoint- ( -4,1) midpoint-(-1,3)
\n" ); document.write( "Let the midpoint b (x,y)
\n" ); document.write( "(x+-4)/2 = -1 and (y+1)/2 = 3
\n" ); document.write( "x = 2 and y=5
\n" ); document.write( "Midpoint is (2,5)
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\n" ); document.write( "Use the same procedure on the following problems.
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\n" ); document.write( "3)
\n" ); document.write( "endpoint-(-3,6) midpoint- (-4,4)
\n" ); document.write( "4)
\n" ); document.write( "endpoint-(6,-10) midpoint (-1,2)
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\n" ); document.write( "\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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