document.write( "Question 1078225: A die is rolled twice. What is the probability of getting either a multiple of 3 on the first roll or a total of 8 for both rolls?\r
\n" ); document.write( "\n" ); document.write( "I got 2/6+5/36, which is 17/36. But that doesn't match an available answer. \n" ); document.write( "
Algebra.Com's Answer #692732 by natolino_2017(77)\"\" \"About 
You can put this solution on YOUR website!
Total Universe=6^2=36 cases-\r
\n" ); document.write( "\n" ); document.write( "First Condition only (First is multiple of 3 and the sum isn't 8) :
\n" ); document.write( "(3,1),(3,2),(3,3),(3,4),(3,6),(6,1),(6,3),(6,4),(6,5),(6,6).
\n" ); document.write( " Favorable cases= 10.\r
\n" ); document.write( "\n" ); document.write( "Second Condition only (First is not a multiple of 3 and the sum is 8) :\r
\n" ); document.write( "\n" ); document.write( "(2,6),(4,4),(5,3)
\n" ); document.write( "Favorable cases=3.\r
\n" ); document.write( "\n" ); document.write( "First and Second condition at the same time:
\n" ); document.write( "(3,5),(6,2)
\n" ); document.write( "favorable cases=2.\r
\n" ); document.write( "\n" ); document.write( "Total favorable cases=10+3+2=15.\r
\n" ); document.write( "\n" ); document.write( "So P()= 15/36 =5/12\r
\n" ); document.write( "\n" ); document.write( "#natolino\r
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