document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1078207>Question 1078207</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the area of a rectangle patio A(p)=32 p-p^2 where A(p) is the area in square meters and p is the width of the rectangle in meters<BR>\n" );
document.write( "a) what dimensions give the maximum area of the patio <BR>\n" );
document.write( "b) what is the maximum area of the patio </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #692690 by </B><A HREF=/tutors/aboutme.mpl?userid=htmentor><B>htmentor(1343)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=htmentor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=htmentor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=692690\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The area is maximized when dA/dp = 0 = 32 - 2p -> p = 16 m<BR>\n" );
document.write( "Therefore the area is A(16) = 32*16 - 16^2 = 256 m^2<BR>\n" );
document.write( "Since area = l*w, the length is also 16 m<BR>\n" );
document.write( "Ans: length, width = 16 m; Area = 256 m^2<BR>\n" );
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