document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1078177>Question 1078177</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Teres's boat has a top speed of 12 miles per hour in still water. While traveling on river at top speed, she went 20 miles upstream in same amount of time sge went 49 miles downstream. Find the rate of the river current? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #692659 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=692659\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 20/(12-x) = 49/(12+x)<BR>\n" );
document.write( "12-x/20 = 12+x/49<BR>\n" );
document.write( "3/5-x/20 = x/49+12/49<BR>\n" );
document.write( "subtract x/49+3/5 from both sides:<BR>\n" );
document.write( "-69x/980 = -87/245<BR>\n" );
document.write( "multiply both sides times 980/60<BR>\n" );
document.write( "x = 116/23 = 5.04<BR>\n" );
document.write( "------------------------------------<BR>\n" );
document.write( "Check:<BR>\n" );
document.write( "20/12-5.04 = 49/12+5.04<BR>\n" );
document.write( "20/6.96 = 49/17.04 Use your calculator to see that the answer is correct. </SPAN>\n" );
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