document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1077979>Question 1077979</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Tommy and Zach are starting out at the same position. Tommy runs north at 5 miles per hour and Zach starts to run east 2 hours later at the rate of 8 miles per hour. How long until Tommy and Zach are 16 miles apart? Round to the nearest tenth if necessary.\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #692454 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel1380><B>jorel1380(3719)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel1380><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jorel1380><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=692454\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Tommy has a head start of 5 x 2, or 10 miles.Then Zach runs at 8 mph. Let x be the amount of time Zach runs. Then:<BR>\n" );
document.write( "(10+5x)²+(8x)²=16²<BR>\n" );
document.write( "100+100x+25x²+64x²=256<BR>\n" );
document.write( "89x²+100x-156=0<BR>\n" );
document.write( "(89x-78)(x+2)=0<BR>\n" );
document.write( "x=-2 or 78/89 <BR>\n" );
document.write( "We get a positive value of 78/89, or 0.8764 hours before they are 16 miles apart. &#9786;&#9786;&#9786;&#9786; </SPAN>\n" );
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