document.write( "Question 1077949: a boat travels 70 miles and then comes back, the current was 20 mph the total trip time was 4 hours and 40 minutes, how fast was the boat traveling \n" ); document.write( "
Algebra.Com's Answer #692446 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! a boat travels 70 miles and then comes back, \n" ); document.write( " the current was 20 mph the total trip time was 4 hours and 40 minutes, \n" ); document.write( " how fast was the boat traveling \n" ); document.write( ": \n" ); document.write( "let s = speed of the boat in relation to the water \n" ); document.write( "then \n" ); document.write( "(s-20) = effective speed upstream \n" ); document.write( "and \n" ); document.write( "(s+20) = effective speed downstream \n" ); document.write( ":] \n" ); document.write( "Change 4 hrs, 40 min to hrs: 4 + 40/60 = 4.67 hrs \n" ); document.write( ": \n" ); document.write( "Write a time equation; time = dist/speed \n" ); document.write( "Time downstream + time upstream = 4 hr 40 min \n" ); document.write( " \n" ); document.write( "multiply equation by (s+20)(s-20), cancel the denominators \n" ); document.write( "70(s-20) + 70(s+20) = 4.67(s-20)(s+20) \n" ); document.write( "distribute \n" ); document.write( "70s - 1400 + 70s + 1400 = 4.67(s^2 - 400) \n" ); document.write( "140s = 4.67s^2 - 1866.667 \n" ); document.write( "Arrange as a quadratic equation \n" ); document.write( "0 = 4.67s^2 - 140s - 1866.667 \n" ); document.write( "Using the quadratic formula, I got positive solution \n" ); document.write( "s = 39.977 ~ 40 mph is boat speed \n" ); document.write( "; \n" ); document.write( ": \n" ); document.write( "Check this find the actual time each way \n" ); document.write( "70/20 = 3.5 \n" ); document.write( "70/60 = 1.167 \n" ); document.write( "-------------- \n" ); document.write( "total time 4.667 hrs which is about 4 hrs and 40 min \n" ); document.write( " |